LeetCode - 1. TwoSum

LeetCode - 1. TwoSum

題目 1. Two Sum

找出相加等於target的兩數。

解題思路

題目自帶官方解法。

Code

Java

Runtime 2 ms, Memory 42.7 MB

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class Solution {
    public int[] twoSum(int[] nums, int target) {
        Map<Integer, Integer> map = new HashMap<>();
        for (int i = 0; i < nums.length; i++) {
            int complement = target - nums[i];
            if (map.containsKey(complement)) {
                return new int[] { map.get(complement), i };
            }
            map.put(nums[i], i);
        }
        return null;
    }
}

Python3

Runtime 56 ms,Memory 15.2 MB

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class Solution:
    def twoSum(self, nums: List[int], target: int) -> List[int]:
        hashmap = {}
        for i in range(len(nums)):
            complement = target - nums[i]
            if complement in hashmap:
                return [i, hashmap[complement]]
            hashmap[nums[i]] = i

C#

Runtime 146 ms, Memory 44.8 MB

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public class Solution {
    public int[] TwoSum(int[] nums, int target) {
        Dictionary<int, int> map = new Dictionary<int, int>();
        for(int i = 0; i < nums.Length; i++){
            int num = nums[i];
            int complement = target - num;
            if (map.ContainsKey(complement)){
                return new int[] {map[complement], i};
            }else if(!map.ContainsKey(num)){
                map.Add(num, i);
            }
        }
        return null;
    }
}

Golang

Runtime 9 ms, Memory 4.2 MB

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func twoSum(nums []int, target int) []int {
    mapNum := make(map[int]int)
    for i, num := range nums{
        var complement int = target - num
        // check val is in map
        if val, ok := mapNum[complement]; ok {
            return []int{i, val}
        }
        mapNum[num] = i
    }
    return nil
}

C++

Runtime 9 ms, Memory 11.2 MB

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class Solution {
public:
    vector<int> twoSum(vector<int>& nums, int target) {
        map<int, int> mapNum;
        for(int i = 0; i < nums.size(); i++){
            int num = nums[i];
            int complement = target - num;
            if (mapNum.count(complement) > 0){
                return {mapNum[complement], i};
            } else {
                mapNum.insert({num, i});
            }
        }
        return {-1, -1};
    }
};

C

Runtime ms, Memory MB Reference

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struct number_hash {
  int value;
  int index;
  UT_hash_handle hh;
};

void destroy_table(struct number_hash** table) {
  struct number_hash* curr;
  struct number_hash* tmp;
  
  HASH_ITER(hh, *table, curr, tmp) {
    HASH_DEL(*table, curr);
    free(curr);
  }
}

int* twoSum(int* nums, int numsSize, int target, int* returnSize) {
  struct number_hash* table = NULL;
  struct number_hash* element;
  int* ret = (int*) malloc(2 * sizeof(int));
  int remaining;
  for (int i = 0; i < numsSize; ++i) {
    remaining = target - nums[i];
   
    // Find if there has already been an element such that the sum is target
    HASH_FIND_INT(table, &remaining, element);
    if (element) {
      ret[0] = element->index;
      ret[1] = i;
      break;
    }
   
    // Add the new number to the hash table if it doesn't exist already
    HASH_FIND_INT(table, &nums[i], element);
    if (!element) {
      element = (struct number_hash *) malloc(sizeof(*element));
      element->value = nums[i];
      element->index = i;

      HASH_ADD_INT(table, value, element);
    }
  }
  
  destroy_table(&table);
  
  *returnSize = 2;
  return ret;
}
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